Difference between revisions of "Main Page"

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Revision as of 11:17, 26 March 2015

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$a=1$

$pi={\frac {3}{4}}{\sqrt {3}}+24\int _{0}^{1/4}{{\sqrt {x-x^{2}}}dx}$

Revision as of 11:17, 26 March 2015 (view source) Admin (talk \| contribs) ← Older edit		Revision as of 11:17, 26 March 2015 (view source) Admin (talk \| contribs) Newer edit →
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−	<math>pi=frac{3}{4} sqrt{3}+24 int_0^{1/4}{sqrt{x-x^2}dx}</math>	+	<math>pi=\frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>